Question #b3042

1 Answer
Jan 10, 2017

Answer:

(x + 1)(2x^2 - 5x + 5)

Explanation:

#f(x) = 2x^3 - 3x^2 + 5#.
When x = - 1 --> f(-1) = 0, then one factor is (x + 1)
After division we get:
#f(x) = (x + 1)(2x^2 - 5x + 5)#
The quadratic function #(2x^2 - 5x + 5)# can't be factored because its D < 0
#D = b^2 - 4ac = 25 - 40 = - 15 < 0#
Factored form:
#f(x) = (x + 1)(2x^2 - 5x + 5)#