Question

Question #b3042

Answer 1

(x + 1)(2x^2 - 5x + 5)

Explanation:

`f(x) = 2x^3 - 3x^2 + 5`.
When x = - 1 --> f(-1) = 0, then one factor is (x + 1)
After division we get:
`f(x) = (x + 1)(2x^2 - 5x + 5)`
The quadratic function `(2x^2 - 5x + 5)` can't be factored because its D < 0
`D = b^2 - 4ac = 25 - 40 = - 15 < 0`
Factored form:
`f(x) = (x + 1)(2x^2 - 5x + 5)`