#0.5x+y=5# ?

1 Answer
Jan 14, 2017

See explanation...

Explanation:

I am not sure what answer you are seeking, but here are some ideas:

#0.5x+y=5#

is the equation of a line.

We can find the intersection with the #y# axis by setting #x=0# to get:

#0+y=5#

So the intersection is #(0, 5)#

We can find the intersection with the #x# axis by setting #y=0# to get:

#0.5x+0 = 5#

Multiplying both sides by #2# we find:

#x = 10#

So the intersection is #(10, 0)#

If we subtract #0.5x# from both sides of the original equation, then we get:

#y = -0.5x+5#

This is in slope-intercept form, like:

#y = mx+c#

where #m=-0.5# is the slope.

Alternatively, we can subtract #y# from both sides of the original equation to get:

#0.5x = 5-y#

then multiply both sides by #2# to get:

#x = 10-2y#

This "solves" the original equation for #x# in terms of #y#.

We can graph the equation by drawing a line through #(0, 5)# and #(10, 0)# like this:

graph{(0.5x+y-5)=0 [-4.79, 15.21, -2.88, 7.12]}