Question

Question #d332d

Answer 1

You would need more than 6 days for plan B to cost less

Explanation:

Let the count of days be `d`

Plan A`->$230xxd->$230d`

Plan B`->$1000+$35xxd->$1000+$35d`
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

For Plan B to cost less we have:

`$230d>$1000+$35d`

Subtract `$35d` from both sides

`$230d-$35d>$1000`

`$195d>$1000`

Divide both sides by $195

Did you know you can treat units of measurement the same way you do the numbers. So you can cancel them out. $ is a unit of measurement!

`d> (cancel($)1000)/(cancel($)195) =5.128...`days

The wording of the question implies that the smallest unit of count of time is 1 day. As you may not have part of a day in this context you must round up. So 5.128.. days is read as 6 days

You would need more than 6 days for plan B to cost less