Question

Question #04136

Answer 1

Initial inequality `->120<=x<=180`

Additional weight `->0<=x<=60`

Explanation:

Let `x` be the weight lifted.

Starting point is `120^("lb")` inclusive giving:

`120^("lb")<=x`

End point is `180^("lb")` inclusive giving:

`120<=x<=180`

Subtract 120 from both limiting values

`(120-120)<=x<=(180-120)`

`0<=x<=60`

Answer 2

`60` pounds or less

Explanation:

Ben can lift a maximum of `180` pounds.

So the inequality will contain a "less than or equal to" sign before `180`:

`Rightarrow underline(" " " " " " " " ") le 180`

At the moment, Ben is lifting `120` pounds, but he can lift additional weight.

Let's represent this "additional weight" using `x`:

`Rightarrow 120 + x le 180`

Subtracting `120` from both sides of the inequality:

`Rightarrow 120 + x - 120 le 180 - 120`

`Rightarrow x le 60`

`x` is "less than or equal to" `60`, i.e. Ben can lift an additional weight of `60` pounds or less.