# Under a pressure of 1.2*atm a gas occupies an 8*mL volume in a piston. What pressure develops if the volume is increased to 12*mL?

Jan 16, 2017

${P}_{2} = 0.8 \cdot a t m$
Boyle's Law holds that ${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$ at constant temperature.
And thus ${P}_{2} = \frac{{P}_{1} {V}_{1}}{V} _ 2 = \frac{1.2 \cdot a t m \times 8 \cdot m L}{12 \cdot m L} = 0.8 \cdot a t m$.