Question #2f3e8

To understand better the reaction, the ammonia is generally written as $N {H}_{4} O H$ that is ammonium hydroxide,where $N {H}_{4}$ is like a metallic cation . So you can obtain salt and water.
$2 N {H}_{4} O H + {H}_{2} S {O}_{4} = {\left(N {H}_{4}\right)}_{2} S {O}_{4} + 2 {H}_{2} O$
But it is less right, because the ammonia is present in water as gas in solution and doesn't exist the molecula $N {H}_{4} O H$