Question #d3e91

1 Answer
Jan 23, 2017

#6#

Explanation:

If you want an even number, the number would have to end in an even number. The only even number we have in the above list is #2#.

We are left with #3# numbers. When we pick the first number, there will be #3# numbers left. When we pick the second number, there will be #2# numbers left. When we pick the third number, there will only be #1# number left.

Therefore, the number of numbers that can be formed is given by #3! * 1 = 3 * 2 * 1 * 1 = 6#, where #n! = n(n - 1)(n - 2)(...)(1)#.

Hopefully this helps!