Question #47caf

1 Answer
Feb 2, 2017

Answer:

See the entire solution process below:

Explanation:

First, multiple each side of the the equation by #color(red)(2)# to eliminate the fraction:

#color(red)(2) xx A= color(red)(2) xx 1/2bh#

#2A= cancel(color(red)(2)) xx 1/color(red)(cancel(color(black)(2)))bh#

#2A = 1bh#

#2A = bh#

Now, divide each side of the equation by #color(red)(b)# to solve for #h#:

#(2A)/color(red)(b) = (bh)/color(red)(b)#

#(2A)/b = (color(red)(cancel(color(black)(b)))h)/cancel(color(red)(b))#

#(2A)/b = h#

#h = (2A)/b#