Question

Question #47caf

Answer 1

See the entire solution process below:

Explanation:

First, multiple each side of the the equation by `color(red)(2)` to eliminate the fraction:

`color(red)(2) xx A= color(red)(2) xx 1/2bh`

`2A= cancel(color(red)(2)) xx 1/color(red)(cancel(color(black)(2)))bh`

`2A = 1bh`

`2A = bh`

Now, divide each side of the equation by `color(red)(b)` to solve for `h`:

`(2A)/color(red)(b) = (bh)/color(red)(b)`

`(2A)/b = (color(red)(cancel(color(black)(b)))h)/cancel(color(red)(b))`

`(2A)/b = h`

`h = (2A)/b`