Question #1a65f

1 Answer
Oct 3, 2017

Answer:

#9" years"#

Explanation:

#"we wish to calculate n the number of years"#

#V=(12000/(n+1))+100#

#"here "V=1300#

#rArr1300=(12000)/(n+1)+100#

#"subtract 100 from both sides"#

#1300-100=(12000/(n+1))cancel(+100)cancel(-100)#

#rArr1200=12000/(n+1)#

#rArr1200(n+1)=12000larrcolor(blue)" cross-multiplying"#

#rArr1200n+1200=12000#

#"subtract 1200 from both sides"#

#rArr1200n=10800#

#"divide both sides by 1200"#

#rArrn=10800/1200=9" years"#