# Question #59469

##### 1 Answer

#### Answer:

#### Explanation:

The thing to remember about **density** is that it always tells you the mass of exactly *one unit of volume* of a given substance.

In this case, the density of mercury is said to be equal to *one unit of volume* is equal to

#"13.6 g cm"^(-3) implies "1 cm"^3 "Hg" stackrel(color(white)(acolor(red)("has a mass of")aaaa))(->) "13.6 g"#

You know that the sample of mercury has a volume of **conversion factor** to find the mass of the sample.

Start by converting the volume of the sample to *cubic centimeters*

#5.0 color(red)(cancel(color(black)("mL"))) * "1 cm"^3/(1color(red)(cancel(color(black)("mL")))) = "5.0 cm"^3#

You will thus have

#5.0 color(red)(cancel(color(black)("cm"^3))) * overbrace("13.6 g"/(1color(red)(cancel(color(black)("cm"^3)))))^(color(blue)("the density of Hg")) = color(darkgreen)(ul(color(black)("68 g")))#

The answer is rounded to two **sig figs**.