How do you factor $x^{2} - y^{2} - 8 x + 16$ $x^2-y^2-8x+16$ ?

Question

How do you factor $x^{2} - y^{2} - 8 x + 16$ $x^2-y^2-8x+16$ ?

1 Answer

Impact of this question

2067 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-07T21:10:27

$x^{2} - y^{2} - 8 x + 16 = (x - y - 4) (x + y - 4)$ $x^2-y^2-8x+16 = (x-y-4)(x+y-4)$

Explanation:

The difference of squares identity can be written:

$a^{2} - b^{2} = (a - b) (a + b)$ $a^2-b^2=(a-b)(a+b)$

We can use this with $a = (x - 4)$ $a=(x-4)$ and $b = y$ $b=y$ as follows:

$x^{2} - y^{2} - 8 x + 16 = (x^{2} - 8 x + 16) - y^{2}$ $x^2-y^2-8x+16 = (x^2-8x+16)-y^2$

$x^{2} - y^{2} - 8 x + 16 = {(x - 4)}^{2} - y^{2}$ $color(white)(x^2-y^2-8x+16) = (x-4)^2-y^2$

$x^{2} - y^{2} - 8 x + 16 = ((x - 4) - y) ((x - 4) + y)$ $color(white)(x^2-y^2-8x+16) = ((x-4)-y)((x-4)+y)$

$x^{2} - y^{2} - 8 x + 16 = (x - y - 4) (x + y - 4)$ $color(white)(x^2-y^2-8x+16) = (x-y-4)(x+y-4)$

Science

Math

Humanities

... and beyond

How do you factor $x^{2} - y^{2} - 8 x + 16$ $x^2-y^2-8x+16$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you factor x^2-y^2-8x+16x2−y2−8x+16x^2-y^2-8x+16 ?

1 Answer

Explanation:

Related questions

Impact of this question

How do you factor $x^{2} - y^{2} - 8 x + 16$ $x^2-y^2-8x+16$ ?