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Question #e45e2

1 Answer

Feb 11, 2017

$(4 b - 5) (4 b - 5)$ $(4b-5)(4b-5)$

Explanation:

$16 b^{2} - 40 b + 25$ $16b^2-40b+25$

Factorise.

$16 b^{2} - 20 b - 20 b + 25$ $16b^2-20b-20b+25$

$4 b (4 b - 5) - 5 (4 b - 5)$ $4b(4b-5)-5(4b-5)$

$(4 b - 5) (4 b - 5)$ $(4b-5)(4b-5)$

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