# Question #b8645

$\left\{4 , - 1\right\}$ and $\left\{10 , 2\right\}$
Adding $x - 2 y = 6$ with $- x + 2 {y}^{2} - 2$ term to term we obtain
$2 {y}^{2} - 2 y = 4$
Solving for $y$ we get $y = \left\{- 1 , 2\right\}$ and consequently $x = \left\{4 , 10\right\}$