# How do you solve 5x-3y=-14 and x-3y=2 using elimination?

Nov 5, 2014

$\left\{\begin{matrix}5 x - 3 y = - 14 \\ x - 3 y = 2\end{matrix}\right.$

by subtracting the second equation from the first equation,

$\implies 4 x = - 16$

by dividing by 4,

$\implies x = - 4$.

By plugging $x = - 4$ into the second equation,

$\left(- 4\right) - 3 y = 2$

by adding $4$,

$\implies - 3 y = 6$

by dividing by $- 3$,

$\implies y = - 2$

Hence, the solution is: $\left(x , y\right) = \left(- 4 , - 2\right)$.

I hope that this was helpful.