# What is the simplest radical form of sqrt64?

Feb 20, 2017

$\sqrt{64} = \sqrt{{2}^{6}} = \pm 8$
The "simplest radical form" of $\sqrt{64}$ is $\sqrt{{2}^{6}}$ if we define "simplest form" as a radical of a prime to an integer power.
However. since $\sqrt{{2}^{6}} = \pm {2}^{3}$
The simplest answer to this question is $\pm 8$