Question #dc299

Question

160 views around the world

You can reuse this answer
Creative Commons License

Answer 1

Feb 18, 2017

#5sqrt(5xxn)# or #5(5xxn)^(1/2)#. Whichever one you prefer.

Rewrite the problem:

#=> sqrt((5^3)(n))#

Write #5^3# as #(5^2)(5)#

#=> sqrt((5^2)(5)(n))#

Take the #5^2# out of the square root.

#=> 5sqrt((5)(n))#

This can be rewritten as.

#=> 5(5xxn)^(1/2)#