Question #12fa5
1 Answer
Feb 15, 2017
#x=1#
#x=-1#
Explanation:
Given -
#y=x(x^2-3)#
#y=x^3-3x#
#dy/dx=3x^2-3#
#dy/dx=0=>3x^2-3#
#3x^2-3=0#
#x^2=3/3=1#
#x=+-sqrt1#
#x=1#
#x=-1#
