Can an orbital with a principal quantum number of #n = 2# have an angular momentum quantum number of #l = 2#? True or false?

1 Answer
Feb 15, 2017

Absolutely... false.

What is the definition of the principal quantum number #n#? It's the energy level, if you recall. So, what is #n# for the second energy level?

Recall that #l <= n - 1#, where #l# is the angular momentum quantum number. Here are some questions for you:

  1. What is the orbital shape described by #l = 2#? #s,p,d,# or #f#?
  2. Verify that #l = 2# is impossible for #n - 1# where #n = 2#.

You should find that #l = 2# is only possible for #n >= 3#.