Summer and Jason's present ages add up to #107# years. If #11# years ago Jason's age was four times Summer's age, how old is Jason now?

1 Answer
Feb 17, 2017

Answer:

Jason is #79# years old now.

Explanation:

Let the Summer's age, #11# years ago, be #x# years. As #11# years ago Jason's age was four times Summer's age, Jason's age #11# years ago would have been #4x# years.

Hence, their present ages are #x+11# and #4x+11# and as sum of their ages now is #107# years, we have

#x+11+4x+11=107#

or#5x=107-11-11=85#

i.e. #x=85/5=17#

Hence, #11# years ago, Summer and Jason were #17# and #17xx4=68# years respectively.

and Jason is #68+11=79# years old now.