# Summer and Jason's present ages add up to 107 years. If 11 years ago Jason's age was four times Summer's age, how old is Jason now?

Feb 17, 2017

#### Answer:

Jason is $79$ years old now.

#### Explanation:

Let the Summer's age, $11$ years ago, be $x$ years. As $11$ years ago Jason's age was four times Summer's age, Jason's age $11$ years ago would have been $4 x$ years.

Hence, their present ages are $x + 11$ and $4 x + 11$ and as sum of their ages now is $107$ years, we have

$x + 11 + 4 x + 11 = 107$

or$5 x = 107 - 11 - 11 = 85$

i.e. $x = \frac{85}{5} = 17$

Hence, $11$ years ago, Summer and Jason were $17$ and $17 \times 4 = 68$ years respectively.

and Jason is $68 + 11 = 79$ years old now.