# Question #c0190

It would become a sodium ion with a ${1}^{+}$ charge.
Sodium has atomic number 11, which means that a neutral sodium atom has 11 positively charged protons and 11 negatively charged electrons. When it loses its single valence electron, it then has 10 electrons and 11 protons, producing a ${1}^{+}$ charge.
$\text{11 p"^+" + "10^(-)="1p"^+}$
The formula for a sodium ion is $\text{Na"^+}$.