# Question #5f07e

Aug 20, 2017

No solutions.

#### Explanation:

We have: $f \left(x\right) = {\left(x - 1\right)}^{2} + {\left(x + 1\right)}^{2} - 2 \left(x + 2\right) \left(x - 2\right)$

First, let's set $f \left(x\right)$ equal to zero:

$R i g h t a r r o w {\left(x - 1\right)}^{2} + {\left(x + 1\right)}^{2} - 2 \left(x + 2\right) \left(x - 2\right) = 0$

Let's expand the parentheses:

$R i g h t a r r o w {x}^{2} - 2 x + 1 + {x}^{2} + 2 x + 1 - 2 \left({x}^{2} - 4\right) = 0$

$R i g h t a r r o w 2 {x}^{2} + 2 - 2 {x}^{2} + 8 = 0$

$R i g h t a r r o w 10 \ne 0$

Therefore, there are no solutions to the equation.