Question #5f07e

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Answer 1 · 2017-08-20T22:56:47

No solutions.

We have: #f(x) = (x - 1)^(2) + (x + 1)^(2) - 2 (x + 2)(x - 2)#

First, let's set #f(x)# equal to zero:

#Rightarrow (x - 1)^(2) + (x + 1)^(2) - 2 (x + 2)(x - 2) = 0#

Let's expand the parentheses:

#Rightarrow x^(2) - 2 x + 1 + x^(2) + 2 x + 1 - 2 (x^(2) - 4) = 0#

#Rightarrow 2 x^(2) + 2 - 2 x^(2) + 8 = 0#

#Rightarrow 10 ne 0#

Therefore, there are no solutions to the equation.