# Question #ebb7d

Mar 31, 2017

$4.9 \text{m}$

#### Explanation:

Assuming that the ball is initially at rest and that air resistance can be neglected, the distance covered by the ball in $1 \text{s}$ is

$s = \frac{1}{2} a {t}^{2}$

$= \frac{1}{2} {\left(9.8 \text{ms"^{-2}) (1"s}\right)}^{2}$

$= 4.9 \text{m}$