Question

What is the derivative of `ln3x`?

Answer 1

`dy/dx=1/x`

Explanation:

We will need the standard result:

`d/dx lnx=1/x`

By the rule of logs:

`y=ln3x`
`\ \ \=ln3+lnx`

`:. dy/dx=0+1/x = 1/x`

Or we can implicitly apply the chain rule:

`dy/dx = 1/(3x) * 3 = 1/x`