How do you divide #2x^2-5x-3# by #2x-6# ?
1 Answer
Mar 4, 2017
Explanation:
We can split the numerator up into parts which are monomial multiples of
#(2x^2-5x-3)/(2x-6) = (2x^2-6x+x-3)/(2x-6)#
#color(white)((2x^2-5x-3)/(2x-6)) = (x(2x-6)+1/2(2x-6))/(2x-6)#
#color(white)((2x^2-5x-3)/(2x-6)) = ((x+1/2)color(red)(cancel(color(black)((2x-6)))))/color(red)(cancel(color(black)((2x-6))))#
#color(white)((2x^2-5x-3)/(2x-6)) = x+1/2#