# How do you divide 9x^2-16 by 3x+4?

Nov 4, 2014

Treat your terms of your dividends like digits... However, you also need to consider "missing" terms (in the case of $9 {x}^{2} - 16$, the $x$ term).

For your divisor, you need only divide using the first term

$$             3x - 4
____________
(3x + 4) / (9x^2 +  0x - 16)
- (9x^2 + 12x)
- 12x - 16
- (- 12x - 16)
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