# a) What are the values of #a# and #b# if #x^2+6x-3=(x+a)^2+b#? b) What is the value of #x# if #x^2+6x-3=0#?

##### 1 Answer

a)

b)

#### Explanation:

**Part a**

**Part b**

There are several ways to solve this.

I will use a method called "completing the square".

First remove the constant from the variable side by adding

We want to turn the left side into a squared binomial.

Remember that

So if

then

and

So by adding

Re-writing the left side as a unexpanded squared binomial

and simplifying the right side:

Then using the square root property:

and finally subtracting