# Question #bef4d

Mar 5, 2017

$w = - 1 \pm \sqrt{\frac{5}{6}}$

#### Explanation:

Making $z = {x}^{2}$ we get

$6 {z}^{2} + 7 z - 10 = 0$ Solving for $z$

$z = \left\{- 2 , \frac{5}{6}\right\}$. Following with $z = {x}^{2} = \frac{5}{6}$ contemplating only real solutions for $x$, we have now

${x}^{2} = {\left(w + 1\right)}^{2} = \frac{5}{6}$ then

$w + 1 = \pm \sqrt{\frac{5}{6}}$ and finally

$w = - 1 \pm \sqrt{\frac{5}{6}}$