# Question c59d7

Mar 4, 2017

$- 15 \setminus m {s}^{- 1}$

#### Explanation:

Yes:

$h ' = - 10 t + 5$

In the previous question we established that contact with water occurs at $t = 2$ by solving  −5t^2 + 5t + 10 = 0#.

And:

$h ' \left(2\right) = - 15 \setminus m {s}^{- 1}$