How do you solve #sqrt(4+7x) = sqrt(7x-9)# ?

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Answer 1 · 2017-03-05T22:15:04

There is no value of #x# satisfying this equation.

Given:

#sqrt(4+7x) = sqrt(7x-9)#

Square both sides to get:

#4+7x = 7x-9#

Subtract #7x# from both sides to get:

#4 = -9#

...which is false.

So there is no value of #x# which will make the equation hold.