# How do you solve and find the extraneous solutions for #2\sqrt{4-3x}+3=0#?

##### 1 Answer

Nov 23, 2014

by subtracting

by dividing by

(Notice that it is now clear that this equation has no real solution since the left-hand side cannot be negative.)

by squaring,

by subtracting

by dividing by

which is its extraneous solution.

I hope that this was helpful.