# How do you solve for x in ""^3sqrt(-2-5x)+3=0?

Mar 22, 2018

I tried this:

#### Explanation:

I would try to rearrange and apply the power of $3$ to both sides:
$\sqrt[3]{- 2 - 5 x} = - 3$
raise to power $3$:
${\left(\sqrt[3]{- 2 - 5 x}\right)}^{3} = {\left(- 3\right)}^{3}$
$- 2 - 5 x = - 27$
$- 5 x = 2 - 27$
$5 x = 25$
$x = \frac{25}{5} = 5$