# Question #ef3ef

Mar 21, 2017

I got $9.9 \times {10}^{-} 35 m$ too small to be detected by any human mean.

#### Explanation:

De Broglie waelength $\lambda$ is given as:
$\lambda = \frac{h}{p}$
]Where:
$h = 6.63 \times {10}^{-} 34 J s$ is Planck's Constant;
$p = m v$ is the linear momentum.
We have (after changing into $k g$ and $\frac{m}{s}$):
$\lambda = \frac{6.63 \times {10}^{-} 34}{0.145 \cdot 46.1} = 9.9 \times {10}^{-} 35 m$