What roots of #z^4+z^2+1 = 0# satisfy #abs(z) < 1# ?
2 Answers
Mar 14, 2017
No root is in
Explanation:
Calling
then
but
May 21, 2017
None
Explanation:
Alternatively, note that:
#0 = (z^2-1)(z^4+z^2+1) = z^6-1#
So the roots are all