# For any given even number #sqrtA# that has #m# digits and #A# with #n# digits, is there a relationship between #m# and #n#?

##### 1 Answer

#### Answer:

- if
#n# is even,#m=n/2# - if
#n# is odd,#m=(n+1)/2#

where

#### Explanation:

Let's first look at a few terms and see if we can spot a pattern (I'm including the variable

Since

And so we can see relationships:

and so on.

And so we can calculate

- if
#n# is even,#m=n/2# - if
#n# is odd,#m=(n+1)/2#

Let's test it out:. Let's say