Question

Question #ac65e

Answer 1

`26.5%`, rounded to one decimal place

Explanation:

Let initial velocity be `v_i`, Kinetic energy would be `=1/2mv_i^2`
Given final Kinetic energy `=1/2mv_i^2xx(1+60%)`
`=>` final Kinetic energy `=1/2mv_i^2xx1.60`
If final velocity is `v_f`, comparing with final kinetic energy`=1/2mv_f^2`
`1/2mv_f^2=1/2mv_i^2xx1.60`
`=>v_f=sqrt1.6v_i` .........(1)

Increase in momentum `="Final Momentum"-"Inital Momentum"`
Increase in momentum `=mv_f-mv_i`
% Increase in momentum `=(mv_f-mv_i)/(mv_i)xx100`

Using equation (1) we get
% Increase in momentum `=(msqrt1.6v_i-mv_i)/(mv_i)xx100`
`=>` % Increase in momentum `=(sqrt1.6-1)xx100`
`=>` % Increase in momentum `=26.5`, rounded to one decimal place