Question 0540f

Mar 25, 2017

The velocity is $8.37 \times {10}^{6} \frac{m}{s}$

Explanation:

The relation here is

$p = \frac{h}{\lambda}$

where $\lambda$ is the wavelength of the electron.

Also, since the classical definition of momentum states that

$p = m v$

We can write

mv=h/(lambda)

or $v = \frac{h}{m \lambda}$

Now the numbers

v= (6.63xx10^(-34))/((9.1 xx10^(-31))(8.7xx10^(-11))$= 8.37 \times {10}^{6} \frac{m}{s}$