# Question #3719b

I am interpreting your question as ${2}^{\frac{2}{3}} \cdot {6}^{\frac{1}{3}}$. The answer is $2 \cdot {3}^{\frac{1}{3}} = 2 \sqrt[3]{3}$.
Notice that ${\left(a b\right)}^{c} = {a}^{c} \cdot {b}^{c}$. We can rewrite ${6}^{\frac{1}{3}}$as ${2}^{\frac{1}{3}} \cdot {3}^{\frac{1}{3}}$.
The question thus becomes ${2}^{\frac{2}{3}} \cdot {2}^{\frac{1}{3}} \cdot {3}^{\frac{1}{3}}$. However, ${a}^{b} \cdot {a}^{c} = {a}^{b + c}$. We can rewrite ${2}^{\frac{2}{3}} \cdot {2}^{\frac{1}{3}}$ as ${2}^{\frac{2}{3} + \frac{1}{3}} = {2}^{1} = 2$.
The final answer is $2 \cdot {3}^{\frac{1}{3}}$. We can also write this using radical form: $2 \sqrt[3]{3}$