Question #5d932

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Answer 1 · 2017-07-16T22:16:59

$V_{1} = 318$ $V_1 = 318$ $mL$ $"mL"$

We're asked to find the original volume of $F_{2}$ $"F"_2$ using gas equations.

To do this, we can use the pressure-volume relationship of gases, illustrated by Boyle's law:

$P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1 = P_2V_2$

where

We need the units for pressure to be consistent, so let's convert the $900$ $900$ $torr$ $"torr"$ quantity to $atm$ $"atm"$ :

$900cancel("torr")((1color(white)(l)"atm")/(760cancel("torr"))) = 1.18$ $"atm"$

Plugging in known values, and solving for the original volume, $V_1$ , we have

$V_1 = (P_2V_2)/(P_1) = ((1.5cancel("atm"))(250color(white)(l)"mL"))/(1.18cancel("atm")) = color(red)(318$ $color(red)("mL"$

which I'll round to $3$ significant figures, the amount given for the other volume measurement.