Question #9ebb1

1 Answer
Mar 30, 2017

#1Al(OH)_2+3HC_2H_3O_2 rarr 1Al(C_2H_3O_2)_3 +3H_2O#

Explanation:

Here's a suggestion:

Treat the acetate ion (the #C_2H_3O_2 in the formulas) as a single unit, because it does not change in the process. This will greatly simplify the task, as your equation will now look like this:

#Al(OH)_3 + HA rarr AlA_3 + H_2O#

where I substitute #A# in place of #C_2H_3O_2#

Place a "1" in front of #Al(OH)_3# and also in front of the #AlA_3#
Now, the #Al# atoms balance.

Place a "3" in front of #HA# because you must balance the three #A# (acetate) that now appear on the right side.

Finally, you have a total of three oxygen atoms and six hydrogen atoms on the left side - just enough for three water molecules on the right.