# Question 9ebb1

Mar 30, 2017

$1 A l {\left(O H\right)}_{2} + 3 H {C}_{2} {H}_{3} {O}_{2} \rightarrow 1 A l {\left({C}_{2} {H}_{3} {O}_{2}\right)}_{3} + 3 {H}_{2} O$

#### Explanation:

Here's a suggestion:

Treat the acetate ion (the C_2H_3O_2 in the formulas) as a single unit, because it does not change in the process. This will greatly simplify the task, as your equation will now look like this:

$A l {\left(O H\right)}_{3} + H A \rightarrow A l {A}_{3} + {H}_{2} O$

where I substitute $A$ in place of ${C}_{2} {H}_{3} {O}_{2}$

Place a "1" in front of $A l {\left(O H\right)}_{3}$ and also in front of the $A l {A}_{3}$
Now, the $A l$ atoms balance.

Place a "3" in front of $H A$ because you must balance the three $A$ (acetate) that now appear on the right side.

Finally, you have a total of three oxygen atoms and six hydrogen atoms on the left side - just enough for three water molecules on the right.