# Question #0753c

Jul 27, 2017

${P}_{2} \approx 18. L$

#### Explanation:

It depends on many more factors than just volume and pressure, of course, but relying upon those factors only:

${P}_{1} {V}_{1} = n R T = {P}_{2} {V}_{2}$
$\therefore {P}_{1} {V}_{1} = {P}_{2} {V}_{2}$

$1.0 a t m \cdot 15 L = 0.85 a t m \cdot {V}_{2}$
${P}_{2} \approx 18. L$