Question #d7127

1 Answer
Apr 1, 2017

Answer:

#"speed of train is :"18.53" "m/s#

Explanation:

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#"As the train moves on curvilinear path,a centrifugal force"#
#"occurs on the pendulum bob."#

#tan theta=(m*v^2/r)/(mg)#

#tan theta=cancel(m)*v^2/r*1/(cancel(m)g)#

#tan theta=v^2/(r g)#

#v^2=r g tan theta#

#v:"speed of train"#

#r:400 m#

#theta:5^o#

#g:9.81" "N/(kg)#

#v^2=400*9.81*tan 5^o#

#v^2=343.31#

#v=sqrt(343.31)#

#v=18.53" "m/s#