# Question 94672

Apr 2, 2017

The new pressure $\text{P"_2=420\ "kPa}$

#### Explanation:

The general equation of ideal gases follows the following form:
$\left({\text{P"_1*"V"_1)/("R"*"T"_1)=("P"_2*"V"_2)/("R"*"T}}_{2}\right)$ .......... (1)
At constant temperature, ${\text{T}}_{1}$ = ${\text{T}}_{2}$. Thus, the equation Form (1) is reduced to: ${\text{P"_1*"V"_1="P"_2*"V}}_{2}$, which will lead to the following form:
${\text{P"_2=("P"_1*"V"_1)/"V}}_{2}$ ................. (2)
"P"_2=(42\ "kPa"*20\ "L")/(2\ "L")#
So, $\text{P"_2=420\ "kPa}$
With kind regards: Mamdouh Younes