# Question #e9b39

Apr 8, 2017

The ratio is $= 2.45$

#### Explanation:

The period of a pendulum is

${T}_{e} = 2 \pi \sqrt{\frac{l}{g} _ e}$

On the moon the period will be

${T}_{m} = 2 \pi \sqrt{\frac{l}{g} _ m}$

The ratio will be

${T}_{m} / \left({T}_{e}\right) = \frac{\sqrt{\frac{l}{g} _ m}}{\sqrt{\frac{l}{g} _ e}}$

$= \sqrt{{g}_{e} / {g}_{m}}$

$= \sqrt{\frac{9.8}{1.63}}$

$= 2.45$