Question #e9b39

Question

1559 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-08T11:23:29

The ratio is #=2.45#

The period of a pendulum is

#T_e=2pisqrt(l/g_e)#

On the moon the period will be

#T_m=2pisqrt(l/g_m)#

The ratio will be

#T_m/(T_e)=sqrt(l/g_m)/sqrt(l/g_e)#

#=sqrt(g_e/g_m)#

#=sqrt(9.8/1.63)#

#=2.45#