How do you simplify #sqrt((3x^3)/(64x^2))#?

1 Answer
Apr 5, 2017

Answer:

#sqrt(3x)/8#

Explanation:

Remember that if you dividing under a root, you can split it into two separate roots:

#sqrt((3x^3)/(64x^2)) = (sqrt(3x^3))/(sqrt(64x^2)) = (sqrt(3x xx x^2))/(sqrt(64x^2)#

Now find the square roots where you can:

#(sqrt(3x xx color(red)(x^2)))/(sqrt(color(blue)(64x^2)))=(color(red)(x)sqrt(3x))/(color(blue)(8x))#

Now simplify:

#sqrt(3x)/8#

OR you could simplify under the root first:

#sqrt((3x^3)/(64x^2)) = sqrt((3x)/(64))#

#= sqrt(3x)/8#