# Question #04d04

Apr 7, 2017

2d and 3f does not exist

#### Explanation:

Principal quantum number n = 1, 2, 3, 4

Azimthual quantum number l =(n - 1) = 0 for s, 1 for p, 2 for d , 3 for f

Magnetic quantum number m = (-l, 0 + l)

For $n = 1$ Magnetic quantum number $m$ is $0 = 1 s$ orbital

For $n = 2$ Magnetic quantum number $m$ is $\left(- l , 0 + l\right) = 2 p$

For $n = 3$ Magnetic quantum number $m$ is $\left(- 2 , - l , 0 + l , + 2\right) = 3 d$

for $n = 4$ magnetic quantum number $m$ is $\left(- 3 , - 2 , - 1 , 0 , 1 , 2 , 3\right) = 4 f$

$2 d$ and $3 f$ do not exist