Question

Question #7171a

Answer 1

`(x^2y^2)/(x^2+y^2)`

Explanation:

the denominator `y^-2+x^-2` can be written as

`1/y^2+1/x^2`

`=(x^2+y^2)/(x^2y^2)`

Now;
`1/(y^-2+x^-2) = (y^-2+x^-2)^-1`

`=((x^2+y^2)/(x^2y^2))^-1`

`=color(red)((x^2y^2)/(x^2+y^2))`