Question #11828

1 Answer
Apr 13, 2017

The filtrate should be colourless, but it depends on the amounts of the chemicals used. See below...


The reaction that takes place will be

#CuCl_2+CaCO_3 rarr CuCO_3 + CaCl_2#

If the reactants consist of the same number of moles of each compound, then, the products will contain no leftover reactants. The precipitate will be green copper carbonate, and the filtrate will be dissolved calcium chloride, which is colourless.

If there is any unused #CuCl_2# in the reaction, it will appear in the filtrate as well, giving it a blue hue.