# How do we make a 1*mol*L^-1 solution of ethanolamine, H_2NCH_2CH_2OH?

$\text{Molarity}$ $=$ $\text{Moles of solute"/"Volume of solution}$
And so we take a $61.08 \cdot g$ mass of ethanolamine, and make it up to a $1 \cdot L$ volume in a volumetric flask:
$\text{Molarity} = \frac{\frac{61.08 \cdot g}{61.08 \cdot g \cdot m o {l}^{-} 1}}{1.00 \cdot L} = 1.00 \cdot m o l \cdot {L}^{-} 1$