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Question #5b4da

1 Answer

Apr 12, 2017

$0$

Explanation:

Remember that $cot(theta)=1/tan(theta)$ .

Then, $cot(90^@)=1/tan(90^@)$ . Recall that $tan(90^@)=oo$ . Then, $cot(90^@)=1/tan(90^@)=1/oo=0$ .

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