What is the de Broglie wavelength for a #"0.01 kg"# particle moving at #"10 m/s"#"?

1 Answer

Answer:

I got: #6.63xx10^-33m#

Explanation:

We know that the deBroglie wavelength is:

#lambda=h/p#

where:

We get:

#lambda=(6.63xx10^-34)/(0.01*10)=6.63xx10^-33# #"m"#,

too small to be detected by any device.

This is indicative of a large, non-quantum system.