# What is the de Broglie wavelength for a "0.01 kg" particle moving at "10 m/s""?

Apr 15, 2017

I got: $6.63 \times {10}^{-} 33 m$

#### Explanation:

We know that the deBroglie wavelength is:

$\lambda = \frac{h}{p}$

where:

• $h = 6.63 \times {10}^{-} 34$ $\text{J"cdot"s}$ is Planck's constant;
• $p = m v$ is the linear momentum.

We get:

$\lambda = \frac{6.63 \times {10}^{-} 34}{0.01 \cdot 10} = 6.63 \times {10}^{-} 33$ $\text{m}$,

too small to be detected by any device.

This is indicative of a large, non-quantum system.